n^2-3n-2754=0

Solution for n^2-3n-2754=0 equation:

n^2-3n-2754=0

a = 1; b = -3; c = -2754;
Δ = b2-4ac
Δ = -32-4·1·(-2754)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-105}{2*1}=\frac{-102}{2}
=-51
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+105}{2*1}=\frac{108}{2}
=54
$